Computer Science, asked by saufi27, 1 year ago

what should be the power of engine required to lift 90 metric tonnes of coal per hour from a mine whose depth is 200m ?​

Answers

Answered by Anonymous
22

\huge\bf{\pink{\mid{\overline{\underline{Answer-}}}\mid}}

\large\bold{50KW}

\huge\bf{\pink{\mid{\overline{\underline{Explanation-}}}\mid}}

\rm\bold{\underline{Given:-}}

\large{mass = 90 \: metric \: tonnes}

\large{height = 200metre}

\rm\bold{\underline{To \:find:-}}

power of engine to to lift 90 metric tonnes.

\rm\bold{\underline{Solution:-}}

mass of coal to be lifted,

\large{m = 90 \: metric \: tonnes}

\large{ =  > 90 \times 1000kg}

\large{=  > 9 \times  {10}^{4} kg}

height = 200 m

time during, which the coal is lifted.

\large{t = 1h = 60 \times 60}

\large{ =  > 3600s}

work done to lift the coal,

\large\boxed{w = mgh}

\large{ =  > (9 \times  {10}^{4} )(10)(200m)}

\large{18 \times  {10}^{7} j}

power of the engine required i.e.

\large\boxed{p =  \frac{w}{t}}

\large{ =  >  \frac{18 \times  {10}^{7} j}{3600s}}

\large{=  > 50000w}

\large\boxed{50kw}

Answered by vasu2021
2

Answer:

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