What should be the temperature rise of a brass rod (alpha =2 X 10^-5°C) so as to increase its length by 1%?
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ΔL = increase in length = α L ΔT
=> ΔL/L = α ΔT
=> 1/100 = 2 * 10⁻⁵ * ΔT
ΔT = 500⁰ C
=> ΔL/L = α ΔT
=> 1/100 = 2 * 10⁻⁵ * ΔT
ΔT = 500⁰ C
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