what should be the temperature rise of a brass rod,its coefficient of linear expansion is 2×10 to the power of -5 degree celcius inverse so as to increase its length by 1%.
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Thermal expansion coefficient α is defined by
ΔL = α * L * ΔT, where α = coefficient of linear thermal expansion
L = length of substance, ΔT = change in temperature.
(ΔL / L) * 100 = 100 * α * ΔT
ΔT = 1 / (100 * 2 * 10⁻⁵) = 500°C
ΔL = α * L * ΔT, where α = coefficient of linear thermal expansion
L = length of substance, ΔT = change in temperature.
(ΔL / L) * 100 = 100 * α * ΔT
ΔT = 1 / (100 * 2 * 10⁻⁵) = 500°C
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you can get the answer on Google
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