Question

What should be the value of M' so that the block
does not slide over the triangular wedge? All
surfaces are smooth.
​

Answer 1

Answer:the answer you've had asked is in the attachment below

Explanation:

Answer 2

Explanation:

for mass M

friction will be = N(mu)

$f = mg \cos( \alpha) (u)$

which should be equal to the downward pulling force

${f}^{1} = mg \sin( \alpha )$

$f = {f}^{1}$

$mg \cos( \alpha ) \times u = mg \sin( \alpha )$

→u cos(alpha) = sin(alpha)

thus mass is not the one that affects here. only the angle and coefficient of friction are the factors that should be in above relation.

hope it helps.