Math, asked by archi43316, 11 months ago

what should be the value of n if 3x2-x-n=6 where x= 1​

Answers

Answered by arvindvermargcsm
0

Answer:

(-1)

Step-by-step explanation:

3*2-X-n=6

6-1-n=6

n=(-1)

Answered by ksaikia1977
0

Answer:

-1

Step-by-step explanation:

3×2-x-n=6

given that x=1(so let us put the given value in the above equation)

3×2-1-n=6 (first multiply 3with2)

6-1-n=6 (subtract 1from6)

5-n=6

(now since 5was a positive value so if we take it to the right hand side it will be negative)

-n=6-5

-n =1

(now if we multiply both sides with -1 we get the following result)

n=1

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