what si the hcf of 8463 and 126
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HCF of 72, 126 and 168 is the largest possible number that divides 72, 126 and 168 exactly without any remainder. The factors of 72, 126 and 168 are (1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72), (1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126) and (1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168) respectively.
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Answer:
HCF is 21
Step-by-step explanation:
8463 = 3 x 7 x 13 x 31
126 = 2 x 3² x 7
From prime factorisation thm
HCF(8463,126) = 3 x 7 = 21
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