What smallest number by which 7803 be multipled with so that the product becomes perfect cube
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first find factors of 7803
7803=3×2601
=3×3×867
=3×3×3×289
=3×3×3×17×17
so form pairs of 3 and the number left by that number we should multiply
so here 7803 multiplied by 17
7803=3×2601
=3×3×867
=3×3×3×289
=3×3×3×17×17
so form pairs of 3 and the number left by that number we should multiply
so here 7803 multiplied by 17
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