Question

What sum of money will amount to ruppes 5,445 in 2 years at 10 percent per annum compound interest???​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Principal=4,500\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given:}} \\ \tt: \implies Amount(A) = 5,445 \: rupees \\ \\ \tt: \implies Time(t) = 2 \: years \\ \\ \tt: \implies Rate\% = 5\% \\ \\ \red{ \underline \bold{To \: Find:}} \\ \tt: \implies Principal(p) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies A= p(1 + \frac{r}{100} )^{t} \\ \\ \tt: \implies 5445 = p(1 + \frac{10}{100} ) ^{2} \\ \\ \tt: \implies \frac{5445}{p} = (1 + 0.1)^{2} \\ \\ \tt: \implies 5445 = p \times (1.1)^{2} \\ \\ \tt: \implies 5445 = p\times 1.1\times 1.1 \\ \\ \tt: \implies 5445 =1.21p\\ \\ \tt: \implies p = \frac{5445}{1.21} \\ \\ \green{\tt: \implies p = 4,500\: rupees}$

Answer 2

Answer:

• Principle = ₹ 4,500.

Given :

• Amount = ₹ 5445

• Time = 2 years

• Rate = 10%

To find :

• Principle =?

Step-by-step explanation:

Compound Interest (C. I) => A = p(1 + r/100)ⁿ

Substituting the values in the above formula, we get,

5445 = p(1+10/100)²

5445 = p(110/100)²

5445 = p(1.1)²

5445 = p × 1.1 × 1.1

P = 5445/1.1 × 1.1

P = 5445/1.21

P = 4,500

Thus,

Principle = ₹ 4,500.