What temperature would be necessary to double the volume of a gas initially at s.t.p. if the pressure is
decreased by 50%?
Answers
Answer:
same temperature rahe ga pressure half ho ga then v double karo gay both are inversely so cut jaye gay and T=T ho jaye ga
ans= Given:
At STP
P1 =760 mmHg
V1 = V1
T1 = 273 K
P2 = 50% OF P1
= 380 mmHg
V2 =2V1
T1 = ?
We have,
Gas equation,
fraction numerator straight P subscript 1 straight V subscript 1 over denominator straight T subscript 1 end fraction space equals space fraction numerator begin display style straight P subscript 2 straight V subscript 2 end style over denominator begin display style straight T subscript 2 end style end fraction space
fraction numerator 760 cross times straight V subscript 1 over denominator 273 end fraction space equals space fraction numerator 380 cross times 2 straight V subscript 1 over denominator straight T subscript 2 end fraction
straight T subscript 2 space end subscript space equals space fraction numerator 273 cross times 380 cross times 2 up diagonal strike straight V subscript 1 end strike over denominator 760 cross times up diagonal strike straight V subscript 1 end strike end fraction
straight T subscript 2 space equals space 273 space straight K
The temperature necessary to double the volume of a gas is 273 K or 0 °C.