what the greatest which divides 615 and 963 leaving remainder 6 in each case
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first subtract 6 from both the numbers.
615 - 6= 609
963- 6= 957
HCF of 609 & 957 are:
609 = 3 x 3 x 29
957= 3 x 11 x 29
HCF = 3 x 29 = 87
largest number which divides 615 and 963 leaving remainder 6 in each case is 87.
615 - 6= 609
963- 6= 957
HCF of 609 & 957 are:
609 = 3 x 3 x 29
957= 3 x 11 x 29
HCF = 3 x 29 = 87
largest number which divides 615 and 963 leaving remainder 6 in each case is 87.
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