Question

what type of bond are present in O2 and NaCl .draw their electron dot structure​

Answer 1

Answer:

Explanation:

1) In H2 :

Covalent Bond is present

II) CH4 molecule

Bond present is Covalent bond

Carbon - atomic number 6

Valence electrons--- 4

electronic configuration : 1s² 2s² 2p²

So carbon atom shares its 4 valence electrons with four hydrogen atom to form methane molecule.

III)Cl2

Bond present is covalent bond

Cl- atomic number 17

electronic configuration = 1s²2s²2p⁶3s²3p⁵

each chlorine atom will share its 1 electron each to gain stability.

Iv) O2 molecule

Oxygen has 8 Atomic number

electronic configuration :

1s²2s²2p⁴

Valence electrons - 8

So each oxygen atom shares two pairs of electron hence bond formed is called as Double covalent bod

Answer 2

Answer:

Covalent bond I think sooo