Question

what type of solutions does the pair of equation 5x-4y+8=0 and 10x-8y+16=0

Answer 1

Step-by-step explanation:

may be.

.. polygon

or quadratic.... equation

Answer 2

Given :- what type of solutions does the pair of equation 5x-4y+8=0 and 10x-8y+16=0 ?

Answer :-

comparing both equations

→ 5x - 4y + 8 = 0 => a1x + b1y + c1 = 0

→ 10x - 8y + 16 = 0 => a2x + b12y + c2 = 0

so, we get,

→ a1 = 5 , b1 = (-4) , c1 = 8

→ a2 = 10 , b2 = (-8) , c2 = 16 .

checking now,

→ a1/a2 = 5/10 = 1/2

→ b1/b2 = (-4)/(-8) = 1/2

→ c1/c2 = 8/16 = 1/2 .

since,

→ a1/a2 = b1/b2 = c1/c2 .

therefore, we can conclude that, both straight lines will coincide and,

• The equations will have infinitely many solutions.

Learn more :-

JEE mains Question :-

https://brainly.in/question/22246812

. Find all the zeroes of the polynomial x4

– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.

https://brainly.in/question/39026698