What value of K is the sequence 3k+4,3k-7,k+12 an arithmetic sequence is
Answers
Answered by
1
Hey mate here is ur answer step by step
3k+4+3k-7+k+12
= 3k+3k+k + 4-7+12
=7k-9
hope it helps and mark it brainliest
3k+4+3k-7+k+12
= 3k+3k+k + 4-7+12
=7k-9
hope it helps and mark it brainliest
Answered by
3
T1 = 3k +4
T2 = 3k - 7
T3 = k + 12
Since they are in AP, common difference is constant
T2 - T1 = T3 - T2
=> ( 3k - 7) - (3k + 4) = ( k + 12) - ( 3k - 7)
=> 3k - 7 - 3k - 4 = k + 12 - 3k + 7
=> - 11 = - 2k + 19
=> 2k = 30
=> k = 15
T2 = 3k - 7
T3 = k + 12
Since they are in AP, common difference is constant
T2 - T1 = T3 - T2
=> ( 3k - 7) - (3k + 4) = ( k + 12) - ( 3k - 7)
=> 3k - 7 - 3k - 4 = k + 12 - 3k + 7
=> - 11 = - 2k + 19
=> 2k = 30
=> k = 15
saigullu55:
But option is not there
maybe there is mistake in options
no ur answer is wrong
Similar questions