Math, asked by nikkuksingh, 9 months ago

what value of k the equation 3x-y+8=0 and 6x-ky=-16​

Answers

Answered by gopalakrishna29
7

Answer:

-2

Step-by-step explanation:

6x-ky=-16

6x-2y=-16

-ky+2y=0

-ky=2y

so k=-2

Answered by Hb1996
6

Answer:

k=2

Step-by-step explanation:

3x - y + 8 = 0 \\  =  > 3x - y =  - 8

6x - ky =  - 16 \\ dividing \: the \: above \: equation \: by \: 2 \\  =  >  \frac{6x}{2}  -  \frac{ky}{2}  =  \frac{ - 16}{2}  \\  =  >  \frac{6x - ky}{2}  =  - 8 \\ by \: keeping \: the \: value \:   - 8 \\  =  >  \frac{6x - ky}{2}  = 3x - y \\  =  > 6x - ky = 6x - 2y \\  =  >  - k = \frac{ - 2y}{y}  \\  =  >  -  k =  - 2 =  > k = 2

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