Question

What volume 5 M HCl and 4MHC Should
be mixed to obtain IL of 8MHC).​

Answer 1

Answer: This may help you

Explanation:

40ml of NaOH,Na

2

​

CO

3

​

with strength 5g/l, 13.25g/l respectively

Weight of NaOH=

1000

40×5

​

=200g≡

100

5

​

moles of NaOH

Weight of Na

2

​

CO

3

​

=

1000

13.25×40

​

=530g=

1000

5

​

moles of Na

2

​

CO

3

​

HCl with hpl needed

1000

5

​

+

1000

5

​

=

1000

10

​

moles

1000

10

​

=N

1

​

V

1

​

=0.05×V

V=

1000

200

​

lit of HCl ≈ 200ml HCl.