What volume 5 M HCl and 4MHC Should
be mixed to obtain IL of 8MHC).
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Answer: This may help you
Explanation:
40ml of NaOH,Na
2
CO
3
with strength 5g/l, 13.25g/l respectively
Weight of NaOH=
1000
40×5
=200g≡
100
5
moles of NaOH
Weight of Na
2
CO
3
=
1000
13.25×40
=530g=
1000
5
moles of Na
2
CO
3
HCl with hpl needed
1000
5
+
1000
5
=
1000
10
moles
1000
10
=N
1
V
1
=0.05×V
V=
1000
200
lit of HCl ≈ 200ml HCl.
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