Question

What volume in dm3 of KCl is obtained in the following Equation:
2KCIO3 -> 2KCI+ 30,
A.
2 dm3
B. 74.5 dm3
C. 50 dm3
D. 40 dm
3
E. 20 dm3
​

Answer 1

Answer:

ANSWER

Reaction:

2KClO

3

→

Δ

2KCl+3O

2

2 2 3

C+O

2

→

Δ

CO

2

1 1

24 gm = 2 moles of carbon

so 2 mole C requires 2 mole O

2

and this requires KClO

3

=

3

4

mole = 4×

3

122.5

= 163.3gm