Question

What volume of 0.1 HCL are required to neutralize
100 ml of 0.5 N NaOH?​

Answer 1

Answer:

First, calculate the number of moles of NaOH present in 5 grams. The molar mass of NaOH is 40 g/mol.

Number of moles of NaOH in 5 gram =

40

5

=0.125 moles.

The moles of HCl needed = moles of NaOH

M

1

V

1

=M

2

V

2

0.25×V

1

=0.125×1000

V

1

=

0.25

0.125×1000

=500 mL

Option C is correct.

Explanation:

Hope it helps!