What volume of 0.10M HNO3 will completely neutralise 60cm3 of 0.05M Na2CO3 solution
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Answer:
M1V1=M2V2
0.1*V1=0.05*60
V1=0.05*60/0.1
V1=30 cm3
Therefore, volume of 0.10M HNO3 is 30 cm3.
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