Question

what volume of 0.1N HNO3 solution can be prepared from 6.3 g of HNO3​

Answer 1

Answer:

molecular weight of HNO3 = 1 + 14 + 48 = 63

Equivalent weight = mol. wt / valency facrtor

                              = 63 / 1

                              = 63

gram equivalent = weight / equivalent weight

                        = 6.3 / 63

                        = 0.1

N = gram equivalent / volume

volume = gm equivalent / normality

            = 0.1 / 0.1

            = 1 ml

Therefore volume of 0.1N HNO3 is 1 ml.

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