What volume of 10 molar HCl solution must be added to 2M HCl solution to get 2L of 7M HCL solution.please help fast .need it asap.
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Given:
M1 = 10 M
M2 = 2 M
M = 7 M
V = 2 L
To Find:
Volume of 10 M HCl solution.
Calculation:
- Let the volume of 10 M HCl be V1 and the volume of 2 M HCl be V2.
⇒ V1 + V2 = V
⇒ V1 + V2 = 2
⇒ V2 = (2 - V1)
- Using molarity equation, we get:
M1 V1 + M2 V2 = M V
⇒ 10 × V1 + 2 × (2 - V1) = 7 × 2
⇒ 10 × V1 + 4 - 2 × V1 = 14
⇒ 8 × V1 = 14 - 4
⇒ V1 = 10 / 8
⇒ V1 = 1.25 L
- Now, V2 = 2 - 1.25 = 0.75 L
- Hence, 1.25 L of 10 M HCl solution must be added to 0.75 l of 2 M HCl solution to get 2L of 7M HCL solution.
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