Question

what volume of 10M h2so4 is needed to prepare 1litre of 0.25M h2so4?

Answer 1

Logic Used:

1) Both Components must have same moles.

Moles = Molarity *Volume of solution

Question needs much more clarification but we dont have other data,so we are equating moles of both components. 

Steps:

 $M_1= 10M ,</p><p>V_1=? \\ M_2= 0.25M , V_2 = 1000mL$

So,By Using Logic:

$M_1*V_1=M_2*V_2\\ => 10M*V_1=0.25*1000mL \\ =>V_1 = 25mL$

Hence, 25mL of 10M $H_2SO_4$ is needed to prepare 1 Litre of 0.25M $H_2SO_4$ .