What volume of 36 N and 1 N sulphuric acid must
be mixed to get 1 L.of 6 N
sulphuric acid
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x + y = 1
total moles H2SO4 = 36 x + y = 1 L x 6 M = 6
x+y=1
36x+y = 6
x = 1-y
36 - 36 y + y = 6
36 - 35y=6
- 35y= -30
y = 0.857 L
x = 1 - 0.857=0.143 L
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