Question

what volume of 6M HCl and 2M HCl should be mixed to get 4 litres of 3M HCl

Answer 1

here is your answer OK


Let us suppose that the volume of 6M HCl (V1) = x L

So, Volume of 2M HCl required to make 1L of 3M HCl (V2) = (1-x) L

Let us take M1 = 6M and M2 = 2M,

We know that, Molarity of a mixture is given by the equation :

(M1V1 + M2V2) / (V1 + V2) = M3

[6x + 2(1-x)] / 1 = 3

6x - 2x + 2 = 3

4x = 1

x = 1/4 = 0.25 L

Therefore, Volume of 6M HCl = 0.25L

and Volume of 2 M HCl = 1-0.25 = 0.75 L