Question

What volume of acetone contain the same number of molecule as are present in 360 ml of water? 0H20 = 1.0 g/ml Cacetone = 0.800 g/cm (1) 1450 ml (2) 1000 ml (3) 550 ml (4) 725 ml mlo​

Answer 1

Answer:

For

BO_(2)

<br>

n_("atom")=14/92xx3

<br> For

A_(2)O_(3)

<br>

W/14xx5=14/92xx3

<br> W=13.5 gm <br>

d=W/V

<br>

1.5=13.5/V

<br>

V=13.5/1.5 =9 mL