Question

What volume of air at n.t.p containing 21% of oxygenby volume is required to completely burn 1000 g of sulphur containing 4% incombustible matter?

Answer 1

HEYA......


S + O2 → SO2 

1mol S reacts with 1 mol O2 


You have 1000g S with 4% impurity: 

Mass of pure S = 96/100*1000 = 960g S 


Molar mass S = 32g/mol 

960g = 960/32 = 30 mol S 


From the balanced equation you require 30 mol O2 

At STP ,

1 mol O2 = 22.4L 
30 mol O2 = 30*22.4 = 672 L of O2 


Volume of air required = 100/21*672 = 3200 L air required.



TYSM.....$GOZMIT

Answer 2

Volume of air required is 3200 litres

Hope it will help u all!!!!