what volume of Cl2 at STP would be evolved by adding 17.4g of MnO2 in HCl solution
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SOLUTION-;
- molar mass =36.4
- Mn O2 : 54.9 + 32 = 86.9
- 4 moles of HCl = 145.6 grams reacts with 1 mole of Mn O2 ie., 86.9 grams..
- So mass of HCl that reacts with 5.0 grams of Manganese dioxide :
- 5 * 145.6 / 86.9 = 8.377 grams of HCl.
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