What volume of CO2 is obtained at STP by heating 4 g of CaCO3
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Answer:
Given that ,
mass of CaCO3 , W = 4g
Now ,
CaCO3(s) ------------->CaCO (s) + CO2 (g)
100g 22.4 lit
4g ---------------------------------> ?X
Now ,
X/22.4 lit = 4g/ 100g
=> X= 4/100×22.4lit
=> X = 0.896 lit
=> X= 896 ml
#volume of CO2 obtain = 896 ml
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