What volume of co2 is obtained at stp by heating 4g of caco3
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Answered by
94
CaCO3-------> CaO+CO2
hence
mole of CaCO3=mole of CO2
mole of CaCO3=given weight/molecular weight
=4/100=0.04
so, mole of CaO =0.04
now use gas formula
PV=nRT
V=nRT/p
=0.04(RT/p)
use T , P and R value at STP
hence
mole of CaCO3=mole of CO2
mole of CaCO3=given weight/molecular weight
=4/100=0.04
so, mole of CaO =0.04
now use gas formula
PV=nRT
V=nRT/p
=0.04(RT/p)
use T , P and R value at STP
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