Question

What volume of H2O2 solution of 22.4 volume strength is required to liberate 2240 mL of O2 at NTP

Answer 1

Answer : The volume of $H_2O_2$ solution of 22.4 volume strength required to liberate 2240 ml of $O_2$ at NTP is, 100 ml

Explanation :

Volume strength : It tells about that the volume of oxygen released on decomposition.

$2H_2O_2(l)\overset{\Delta}\rightarrow H_2O(l)+\frac{1}{2}O_2(g)$

As we are given that 22.4 volume strength of $H_2O_2$ solution this means that 1 ml of $H_2O_2$ solution produces 22.4 ml of oxygen at NTP.

As, 22.4 ml of oxygen liberated from 1 ml volume of $H_2O_2$ solution

So, 2240 ml of oxygen liberated from $\frac{2240}{22.4}=100ml$ volume of $H_2O_2$ solution

Hence, the volume of $H_2O_2$ solution of 22.4 volume strength required to liberate 2240 ml of $O_2$ at NTP is, 100 ml