Question

what volume of NH3 gas at STP would be needed to prepare 100 ml of 2.5molar ammonium hydroxide solution?

Answer 1

5.6 lit is correct answer because

Molecular weight of NH4OH =35

Now

35g of NH4OH is needed to prepare 1 M solution in 1 liter

⇒ 35g NH4OH is 1 L solution  = 1 molar solution

⇒ 2.5 x 35g NH4OH is 1 L solution = 2.5 molar solution

⇒ 2.5 x 35 / 10 g NH4OH is 100L solution = 2.5 molar solution

⇒ 8.75 g NH4OH was dissolved

NH3 + H2O → NH4OH

for 35g NH4OH, NH3  needed = 22.4 L at S.T.P

⇒ for 8.75 g NH4OH, NH3 needed = 22.4/35 x 8.75 L

= 5.6L

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Answer 2

Answer:

Explanation:

Brainly.in

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Secondary School Physics 11+6 pts

What volume of NH3 gas at STP would be needed to prepare 100 ml of 2.5molar ammonium hydroxide solution?

Report by Savaliyamukundov6dwu 14.09.2017

Answers

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karushi

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> Molecular weight of NH4OH =35

Now ,

35g of NH4OH is needed to prepare 1 M solution in 1 liter

⇒ 35g NH4OH is 1 L solution = 1 molar solution

⇒ 2.5 x 35g NH4OH is 1 L solution = 2.5 molar solution

⇒ 2.5 x 35 / 10 g NH4OH is 100L solution = 2.5 molar solution

⇒ 8.75 g NH4OH was dissolved

NH3 + H2O → NH4OH

for 35g NH4OH, NH3 needed = 22.4 L at S.T.P

⇒ for 8.75 g NH4OH, NH3 needed = 22.4/35 x 8.75 L

= 5.6L