Question

What volume of oxygen at stp is needed to completely burn 15.0g of methanol?

Answer 1

Methanol burns as follows,

2CH3OH + 3O2--> 2CO2 + 4H2O

Molar mass of Methanol=12+1x4+16x1=32 g

To burn 64 g of methanol completely, 96 g of oxygen is reqd.

∴ To burn 15 g of methanol, 96/64 x 15=22.5 g of oxygen is reqd.

32 g of oxygen = 22.4 L of oxygen

∴ 22.5 g of oxygen = 22.4/32 x 22.5=15.75 L of oxygen

Therefore, 15.75 L of oxygen is reqd. to burn 15 g of methanol completely.

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