Question

what volume of oxygen at STP is required to complete turn 200 ml of acetylene? ​

Answer 1

Hi friend,

Combustion reaction of acetylene:

C2H2 + 52O2 → 2CO2 + H2O

According to reaction,

At STP;

1 mole of acetylene that is 22.4L require 5/2 moles of oxygen that is 52×22.4 = 56L for complete combustion.

Now, 200cm3 or 0.2L of acetylene will require = 5622.4×0.2 = 0.5L or 500cm3 of oxygen for complete combustion

1 moles of acetylene that is 22.4L produce 2 moles that is 2×22.4 = 44.8L of carbon dioxide.

Now, 0.2L of acetylene will produce = 44.822.4×0.2 = 0.4L or 400cm3 of carbon dioxide.

Hope this helps you...

Answer 2

Answer:

Thus volume of O2 required = 500 cm3 at S.T.P. According to Gay Lussac's law of gaseous volumes.

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