Question

What volume of oxygen gas measured at 0 Celsius and 1 atm is needed to burn completly 1 l of propane gas under the same condition

Answer 1

Hi friend,

Explanation :-


As we can deduce the mol of propane so, mol(propane) = x

Equation :-

5O2 + C3H8 => 3 Co2 + 4H2O

According to this formula , we can get O2 = mol(propane) ×5

Thus , we put the formula in other formula

PV = nRt

Where p is 101.325 kpa

N is the mol of oxigen

R is 8.31 ( which is standered valu )

T = 273K

With , V (the volume ) being unknown

So, we can deduce the answer...i hope it helps you