What volume of propane is burnt for every 500cm3 pf air used in the reaction under the same conditions ? (assuming oxygen is 1/5 of air ) c3h8 +5o2=3co2+4H2O
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C3H8 + 5 O2 ----> 3 CO2
propane = 1v , oxygen = 5v therefore volume of propane required = 100 cm3
propane = 1v , oxygen = 5v therefore volume of propane required = 100 cm3
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