What weight of 60% pure sulphuric acid is required to decompose 25gram of chalk(CaCO3).help me fast guys. Please.....
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Answered by
27
The decomposition reaction :-
H2SO4 +CaCO3 ? CaCO3 + CO2 + H2O
1mol of sulphuric acid decomposes 1mol of calcium carbonate.
50g of calcium carbonate corresponds to 0.5mol of calcium carbonate.
Therefore,0.5mol of sulphuric acid is required to decompose 0.5mol of calcium carbonate.
0.5mol corresponds to 49g of H2SO4
As 60% of sulphuric acid is there, 60% of H2SO4 required =(100×49/60)g=81.67g
H2SO4 +CaCO3 ? CaCO3 + CO2 + H2O
1mol of sulphuric acid decomposes 1mol of calcium carbonate.
50g of calcium carbonate corresponds to 0.5mol of calcium carbonate.
Therefore,0.5mol of sulphuric acid is required to decompose 0.5mol of calcium carbonate.
0.5mol corresponds to 49g of H2SO4
As 60% of sulphuric acid is there, 60% of H2SO4 required =(100×49/60)g=81.67g
Answered by
16
Answer:40.833 gm H2SO4
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