Question

what weight of callcium will have same number of atom are present in 3g of alluminium​

Answer 1

Answer:

4.6 gms (approximately )

Explanation:

m wt of Al-26

then 26gms contain 1mole of Al

3g contain how many moles of Al

=3/26 moles

m.wt of Ca-40

then the wt of Ca that same no.of atoms of Al present is

(3/26)×40

=4.6gms (approximately )