What weight of co2 will occupy the same volume as 40 gm of o2 at ntp?
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Answer:
V=1.18L
Explanation:
In order to solve this problem we would use the Ideal Gas Law formula PV=nRT
P= Pressure in atm
V= Volume in L
n= moles
R= Ideal Gas Law Constant
T= Temp in K
STP is Standard Temperature and Pressure which has values of
1atm and 273K
2.34gCO2 must be converted to moles
2.34gCO2x1mol44gCO2=0.053mols
P=1atm
V=???L
n=0.053mols
R=0.0821atmLmolK
T=273K
PV=nRT becomes
V=nRTP
V=0.053mols(0.0821atmLmolK)(273K)1atm
V=1.18L
HOPE IT HELPS YOU..
Answer:
V=1.18L
Explanation:
In order to solve this problem we would use the Ideal Gas Law formula PV=nRT
P= Pressure in atm
V= Volume in L
n= moles
R= Ideal Gas Law Constant
T= Temp in K
STP is Standard Temperature and Pressure which has values of
1atm and 273K
2.34gCO2 must be converted to moles
2.34gCO2x1mol44gCO2=0.053mols
P=1atm
V=???L
n=0.053mols
R=0.0821atmLmolK
T=273K
PV=nRT becomes
V=nRTP
V=0.053mols(0.0821atmLmolK)(273K)1atm
V=1.18L
HOPE IT HELPS YOU..
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