Question

What weight of each element is present in 1.5 moles of sodium sulphide, Na2SO3 ?

Answer 1

Na2SO3
For Na : 1.5×2×23= 69g
S : 1.5×1×32 = 48g
O : 1.5×3×16 = 72g
Hope it helps...

Answer 2

Explanation:Na2SO3

Na= 23 u

S= 32 u

O= 16 u

so,

Na = 1.5×2×23 = 69 g

S = 1.5×1×32 = 48 g

O = 1.5×3×16 = 72

hope it helps✨

please mark me as brainliest ✨✨