Chemistry, asked by sgour7719, 11 months ago

What weight of each element is present in 1.5 moles of sodium sulphide, Na2SO3 ?

Answers

Answered by riturajbabu
3
Here n (no. Off moles)=1.5 ok now M (molar mass)=NaSO3=23+32+16×3=113g so,n=m÷M therefore 1.5×113=mass and that is the weight hope it hepls
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