A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 12 cm, find its breadth. Which encloses more area, the square or the rectangle?
Answers
perimeter = 40 cm
perimeter of rectangle =40 cm
length = 12 cm
2 (l+b) = 40 cm
l+b =20 cm
b = 20 - 12
= 8 cm
area of square = 10×10=100 cm .Sq
area of rectangle = 12×8=96 cm .Sq.
Solution:
Given Question:
A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 12 cm, find its breadth.
Find:
Let's find which encloses more area, the square or the rectangle?
Given:
10 cm = side of the square.
Length of wire = Perimeter of square = 4 × side = 4 × 10 cm.
Length of teenage = 12 cm.
Perimeter of rectangle = length of wire = 40 cm.
Perimeter if rectangle → 2(L + B)
→ 40 = 2 (12 + B)
or → 40/2 = 12 + B
hence, → B = 20 - 12 = 8 cm
Therefore, 8 cm is the breadth of the rectangle.
Area of the square = (side)²
→ 10 cm × 10 cm = 100 cm²
Area of the rectangle = (L × B)
→ 12 cm × 8 cm = 96 cm²
Therefore, the square enclose more even though it's a perimeter is the same as that of the rectangle.