What weight of hydrogen would be sufficient to completely reduce 7.95g of CuO?
(Cu=63.5,O=16,H=1)
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Answer:
Cu=63.5
Explanation:
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Explanation:
79.5g of CuO is sufficient to reduce 2g of hydrogen
hence
7.95g of CuO,, ,, ,, ,, ,,2g ×7.95)/79.5
=2×7.95×100)/79.5×100
=2×795)/7950
=2/10
=0.5g
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