Question

What Weight of Iron(||) sulphide is formed when 40g of sulphur reacts with Iron? (Atomic no. of Iron = 56, sulphur =32).

Answer 1

Weight of S =40g
S. + Fe →FeS
32g+56g.=88g

Therefore, 32g of S react to give 88g of FeS
Then, 40g of S to give =88/32×40


= 110g of FeS
(Ans)

Hope it Helps...!

Answer 2

Answer:

atomic mass of Fe(iron)= 56

atomic mass of sulphur= 32

reaction: Fe + S = FeS

56 + 32= 56 + 32

56 + 32= 88g of ferrous Sulphide

32 g of sulphur react with iron to give

88 g of iron sulphide.

40g of sulphur will give = 88/32×40

= 110g of ferrous Sulphide(FeS)

Explanation:

HENCE, 40 g of sulphur will give 110 g of FeS(ferrous sulphide)...