Question

What will be boiling point of 0.1 m Urea(aq) solution?

( kb = 0.52 K Kg mo1
-1
)


(A) 273.67 K
(B) 373.2 K
(C) 373.63 K
(D) 273.2 K​

Answer 1

Answer:

see the attachment please

Explanation:

Hope the answer will help you

Answer 2

Given:

The molality of urea, m = 0.1

Kb = 0.52 K kg/mol

To Find:

The boiling point of the given aqueous urea solution, i.e., Tb.

Calculation:

- The boiling point of pure water, T = 373.15 K

- The elevation in boiling point is given as:

ΔTb = Kb × m

⇒ (Tb - T) = 0.52 × 0.1

⇒ (Tb - 373.15) = 0.052

⇒ Tb = 373.15 + 0.052

⇒ Tb = 373.202 K

- So, the correct answer is option (B) 373.2 K .