what will be duration of day with earth if shrinks to 1/64 of its original volume mass remaining unchanged
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Answer:
assume,
earth is solid sphere,
vi=4/3 πr³
vf=1/64 ×vi
= 4πr³/3×64
vf=4/3π (R/4)³
=4/3πr'³
=r/4=r'
earth shrink=means,no external torque I.e 0,
angular momentum is conserved,
Lbefore shrink=Lafter shrink
IiWi =IfWf
2/5MR²Wi=2/5MR²/16 Wf,
Wf=16Wi,
24hr=1 revo.=2πrad,
2πrad/24hr
2π×16/24 rad,
2π/3/2 rad/hr
3/2hr
i.e 1.5 hr or 1:30 hr
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