Question

what will be dy/dx, if y =
$a \sqrt{x} + b + \frac{c}{ \sqrt{x} }$
​

Answer 1

Answer:

Hope it helps

Thank you........

Answer 2

Answer:

$\frac{1}{2\sqrt{x} }(a-\frac{c}{x} )$

Step-by-step explanation:

$y=a\sqrt{x} +b+\frac{c}{\sqrt{x} }\\\\\frac{d}{dx}(a\sqrt{x} +b+\frac{c}{\sqrt{x} })\\\\\frac{dy}{dx}=\frac{a}{2\sqrt{x} }+0- \frac{c}{2\sqrt[3/2]{x} } \\ \\\frac{dy}{dx}=\frac{dy}{dx}=\frac{1}{\sqrt{x} }(a-\frac{c}{x} )\\\\Hope \ it \ is \ clear \ to \ you$