What will be equation if the sum of zeroes is 2 and product of zeroes is —3
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Answer:
x^2 - 2x -3 is the equation
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Step-by-step explanation:
let the given zeroes be x and y
according to problem,
x × y = (-3)
x + y = 2 ....... eq.(1)
we know that (x-y)^2 = (x+y)^2 - 4xy
=} here,
(x-y)^2 = (2)^2-4(-3)
= 4 + 12
= 16
=} x-y = √16
x-y = 4 ......... eq(2)
eq (1) + eq (2)
=} 2x = 6
=} x = 3
by substituting x in eq(1)
=} 3+y = 2
=} y = (-1)
therefore , the zeroes are 3 ,(-1)
=} The equation in terms of k is
(k-3)(k+1)
= k^2 + k - 3k - 3
= k^2 -2k - 3
therefore, the equation is k^2 - 2k - 3
I hope it helps you
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