what will be force between two electrons if distance is increased 4 times? (use Columbus law)
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We know,
Columb's Law :-
Force is inversely proportional to square of distance between them.
e.g F = P/r² -------(1)
Where P is constant.
Let initial Force = F
Now distance between two charge increased 4times.
e.g R = 4r
F' = P/(4r)² = P/16r² = (1/16) P/r²
But P/r² = F according to equation (1)
So,
F' = F/16
Hence Force will be reduce 16 times of initial force.
Columb's Law :-
Force is inversely proportional to square of distance between them.
e.g F = P/r² -------(1)
Where P is constant.
Let initial Force = F
Now distance between two charge increased 4times.
e.g R = 4r
F' = P/(4r)² = P/16r² = (1/16) P/r²
But P/r² = F according to equation (1)
So,
F' = F/16
Hence Force will be reduce 16 times of initial force.
Manish1817:
hi abhi
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