what will be new force if the first mass reduces to it s=1/3 mass and second mass is double
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Let FORCE,F =m.a
1. when new mass is m'= 1/3 ;
the new force F' = (m/3) .a
3F' = ma
3F'= F
so the force gets tripled.
2. when new mass, m" = 2m
the new force ,F" = (2m).a
F"/2 = m.a
F"/2 = F
so the force gets reduced by half.
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