Math, asked by muddy3592, 1 year ago

What will be obtained if 8 is subtracted from the hcf of 168, 189, and 231?

Answers

Answered by harrineananthtoutz8u
10
Hcf 168, 189, and 231 is 21
21-8=13
Answered by Golda
18
Solution :-

H. C. F. of 168, 189 and 231

Prime factorization of 168 = = 2*2*2*3*7

Prime factorization of 189 = 3*3*3*7

Prime factorization of 231 = 3*7*11

Common factors - 3*7

H.C.F. = 21

H.C.F. of 168, 189 and 231 is 21.

Now, 8 is subtracted from H.C.F. of 168, 189 and 231

⇒ 21 - 8 = 13

Answer.
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