Question

what will be percentage increase in momentum of a body when both its mass and velocity are doubled

Answer 1

according to me this is the answer ie 300%
plz correct if wrong
comment if correct

Answer 2

The percentage increase in momentum of the body is $300\%$.

Explanation:

The initial momentum of the body is given by

$P = m\times v$.

Here, m is the mass of the body and v is the velocity of the body.

When both mass and velocity of the body becomes twice, then momentum will be

$P_{f}=2m\times2v$

       $=4mv$

So frictional increase in momentum,

$=\frac{P_{f} -P}{P}$

$=\frac{4mv-mv}{mv} =3$

Therefore, percentage increase in momentum

$=3\times100=300\%$

Thus, the percentage increase in momentum of the body is $300\%$.

#Learn More:

Topic: Momentum

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